7s^2+10s=0

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Solution for 7s^2+10s=0 equation:



7s^2+10s=0
a = 7; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·7·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*7}=\frac{-20}{14} =-1+3/7 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*7}=\frac{0}{14} =0 $

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